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8x^2-12x-308=0
a = 8; b = -12; c = -308;
Δ = b2-4ac
Δ = -122-4·8·(-308)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10000}=100$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-100}{2*8}=\frac{-88}{16} =-5+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+100}{2*8}=\frac{112}{16} =7 $
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